3y^2-16+20=0

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Solution for 3y^2-16+20=0 equation: 



3y^2-16+20=0

We add all the numbers together, and all the variables

3y^2+4=0

a = 3; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·3·4
Δ = -48
Delta is less than zero, so there is no solution for the equation

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